7x^2-56x-3=60

Solution for 7x^2-56x-3=60 equation:

7x^2-56x-3=60

We move all terms to the left:

7x^2-56x-3-(60)=0

We add all the numbers together, and all the variables

7x^2-56x-63=0

a = 7; b = -56; c = -63;
Δ = b2-4ac
Δ = -562-4·7·(-63)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-70}{2*7}=\frac{-14}{14}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+70}{2*7}=\frac{126}{14}
=9
$